shortcuts: connexion locale *en anonyme*

Ça manquait.

shortcuts.py

@@ -92,8 +92,6 @@ def lc_ldap_local(*args, **kwargs):
        qui est problématique).
        
        """
-    auth_dn = secrets.get('ldap_readonly_auth_dn')
-    auth_pw = secrets.get('ldap_readonly_password')
     if os.path.exists('/var/run/slapd/ldapi'):
         ro_uri = 'ldapi://%2fvar%2frun%2fslapd%2fldapi/'
     elif os.path.exists('/var/run/ldapi'):
@@ -101,11 +99,20 @@ def lc_ldap_local(*args, **kwargs):
     else:
         ro_uri = 'ldap://127.0.0.1'
     kwargs["uri"] = ro_uri
-    kwargs["dn"] = auth_dn
-    kwargs["cred"] = auth_pw
+    if not kwargs.has_key('dn'):
+        kwargs['dn'] = secrets.get('ldap_readonly_auth_dn')
+    if not kwargs.has_key('cred'):
+        kwargs['cred'] = secrets.get('ldap_readonly_password')
     kwargs.setdefault("user", current_user)
     return module_qui_a_le_meme_nom_que_sa_classe_principale.lc_ldap(*args, **kwargs)
 
+def lc_ldap_anonymous(*args, **kwargs):
+    kwargs.update({
+        'user': None,
+        'dn': None,
+        'cred': None,
+    })
+    return lc_ldap_local(*args, **kwargs)
 
 class with_ldap_conn(object):
     """Décorateur (instance = decorator) pour les fonctions nécessitant une